How many seconds will the ball be going upward if a ball is thrown vertically upward from the ground with the initial velocity of 56 feet per second and the acceleration due to gravity is #-32 (ft)/t^2#?

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Answer 1 · 2015-03-01T19:17:59

The ball will be going up for 1.75s

#v=u+at#

#v#= final velocity which is zero in this case

#u#=initial velocity

#a#=acceleration = 32ft/s/s

#t#= time

#0=u+at#

#t=(-u)/(a) =(-56)/(-32)=1.75s#