Question

How do you differentiate `y=x^-2(4+3x^-2)`?

Answer 1

You may use the Product Rule where you have:
`y=f(x)g(x)` then;
`y'=f'(x)g(x)+f(x)g'(x)`
In your case:
`y'=-2x^(-3)(4+3x^(-2))+x^(-2)(-6x^(-3))=`
`=-8x^(-3)-6x^(-5)-6x^(-5)=`
`=-8x^(-3)-12x^(-5)`