What are the critical points of #y=2 tan x# on #[0, pi^2]#?

1 Answer
Mar 13, 2015

The function #y=tanx# has no critical points because its derivative is never zero, as you can see:

#y'=1+tan^2x# that is always positive.

The graph is:

graph{tanx [-10, 10, -5, 5]}