Question

How do you simplify `sqrt2/sqrt6`?

Answer 1

Take a one big root as :
`sqrt(2/6)=` and simplyfy getting:
`=sqrt(1/3)=(sqrt(1))/(sqrt3)=1/sqrt(3)=1/sqrt(3)*sqrt(3)/sqrt(3)=`
The last operation is called rationalization and it is used to avoid roots in the denominator:
`=sqrt(3)/3`