How do you graph #x + 2y = -2#?

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Answer 1 · 2015-03-24T08:58:19

Convert the equation to slope-intercept form by solving for #y#.

#x+2y=-2#

(Subtract #x# from both sides.)

#2y=-2-x#

(Divide both sides by 2.)

#(cancel (2)y)/(cancel (2))=(-cancel (2))/(cancel (2))-(x)/(2)#

#y=(-x)/(2)-1#

Values for #x# and #y#:
#x=-2, y=0#
#x=0, y=-1#
#x=2, y=-2#

graph{y=-x/2-1 [-8.03, 6.03, -3.945, 3.085]}