How do you find the slope of the line whose equation is x - 6y + 12 = 0?

1 Answer
Mar 30, 2015

Convert the equation in the standard form #y=mx+q#. Once these manipulations are done, you'll have that the slope is #m#.

So, starting from #x-6y+12=0#, add #6y# at both sides, to get #x+12=6y#. From here, divide both sides by 6, and you have
#x/6+2=y#, which of course is equal to
#y=1/6 x +2#.

So, #m=1/6# and #q=2# (which is actually irrelevant from your point of view. The slope is thus #1/6#.