Question

Question #28efc

Answer 1

By the power rule, the derivative of `f^n(x)= n f^{n-1}(x) f'(x)`.
In your case, `f(x)=3x^2 + 5x + 1`, and `n=3/2`

This means that `n-1=1/2`, and the derivative `f'(x)` is also easy to calculate, since it is `6x+5`.

Putting the pieces together, we can translate the general formula `n f^{n-1}(x) f'(x)` into
`3/2 (3x^2 + 5x + 1)^{1/2} (6x+5)`