How do you rationalize the denominator and simplify the answer for #2/(5+sqrt3#?

1 Answer
Mar 31, 2015

#1/11#( 5-#sqrt3#)

To rationalize the denominator, multiply the numerator as well as denominator by the conjugate of 5+#sqrt3#, which is 5-#sqrt3#.

#2/(5+sqrt3# * #(5-sqrt3#)/(5-#sqrt3)#

Since (5+#sqrt3#)(5-#sqrt3#) equals to (25-3)=22, we have the given fraction equal to #2/22# (5-#sqrt3)#

=#1/11# (5-#sqrt3#)