Question

How do you rationalize denominator `(8)/ (sqrt5+sqrt2)`?

Answer 1

`8/3` (`sqrt5` -`sqrt2`)

Multiply the numerator and the denominator by the conjugate of `sqrt5` +`sqrt2` , which would be `sqrt5` - `sqrt2`

On simplification we would have `8/3`(`sqrt5`-`sqrt2`)

[ (`sqrt5`+`sqrt2`)(`sqrt5` -`sqrt2`) = (5-2)=3]