Question

How do you write an equation for the line parallel to `2x-y=4` that goes through (8, -12) in slope-intercept form?

Answer 1

We first write `2x-y=4` in slope-intercept form:

`2x-y=4->` add `y` and subtract `4` on both sides
`2x-4=y->y=2x-4` where `2` is the slope

Now fill in `(8,-12)` (`b` is the new `y`-intercept)

`y=2x+b->-12=2*8+b->b=-28`

So the new equation is: `y=2x-28`