How do you simplify and solve #(4^(2x)+3) + (4^(2x)+2) = 320#?

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Answer 1 · 2015-04-04T21:47:01

#4^(2x) *2=315#

#-> 4^(2x) = 315/2#

#->ln(4^(2x)) = ln(315/2)#

#->2xln(4)=ln(157.5)#

#->2x=ln(157.5)/ln(4)#

#-> 2x ~=3.64#

#-> x~=1.82#

Answer 2 · 2015-04-04T21:55:23

Have a look:
enter image source here
At the end I used the change of base of logs where you have:
#log_a(c)=ln(c)/ln(a)#