How do you find the slope and one point on the line that each point-slope equation represents for #y=3+2(x-1)#?

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Answer 1 · 2015-04-06T21:12:29

Gradient is #2# point is #(1,3)#

All you really got to do is to arrange that equation: #y = 3 + 2(x - 1)# in the form below

#y - y_0 = m(x - x_0)#

where #m# is the gradient and the point is #(x_0, y_0)#

#=> y - 3 = 2(x - 1)#

Hence, it's easy to see that #m = 2# and the point is #(1,3)#

Answer 2 · 2015-04-06T21:24:43

Point-slope equation:

#(y-y_1)=m(x-x_1)#

#y=3+2(x-1)#

#y-3=2(x-1)#

#y_1=3# and #x_1=1#

The point is (1,3) and the slope (#m#) is 2.