How do you write #6y = 3x + 4# or #y-x=0# in slope intercept form?

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Answer 1 · 2015-04-07T02:15:15

First Equation:

#6y=3x+4#=

(Divide both sides by 6.)

#y=(3x)/(6)+(4)/(6)#=

#y=1/2x+2/3#

(Slope=#1/2#, y-intercept=#2/3#)

graph{y=1/2x+2/3 [-10, 10, -5, 5]}

Second Equation:

#y-x=0#

(Subtract #x# from both sides.)

#y=x+0#

#y=x#

(Slope=1, y-intercept=0)

graph{y=x [-10, 10, -5, 5]}