Question

How do you find slope of (1,-1); (-2,-6)?

Answer 1

• `[Slope](http://socratic.org/algebra/graphs-of-linear-equations-and-functions/slope)` = `(Rise)/(Run)`
  The `Rise` is the Difference of the Y coordinates of any two points on the line
  And the `Run` is the Difference of the X coordinates of those two points

• If the coordinates of the points are `(x_1,y_1) and (x_2,y_2)`, then `Slope = (y_2-y_1)/(x_2-x_1)`
  Here, the coordinates are `(1,-1)` and `(-2,-6)`

`Slope = (-6-(-1))/(-2-1)=(-6+1)/-3=(-5)/-3=5/3`

The slope of the line passing through points (1,-1) and (-2,-6) is `5/3`

• The graph of the line will look like this:
  graph{y=(5x/3)-(8/3) [-10, 10, -5, 5]}