How to find the slope of a line containing (8,5) (-4,7)?

2 Answers
Apr 7, 2015

Given any two points on a straight line, #(x_1,y_1)# and #(x_2,y_2)#
the slope is defined as
#(Delta y)/(Delta x) = (y_2-y_1)/(x_2-x_1)#

For the given points #(8,5)# and #(-4,7)#
we have
slope #= (7-5)/((-4)-8) = 2/(-12) = -1/6#

Apr 7, 2015
  • #color(green)(Slope= (Rise)/(Run)#

The #Rise# is the Difference of the Y coordinates of any two points on the line
And the #Run# is the Difference of the X coordinates of those two points

  • If the coordinates of the points are #(x_1,y_1) and (x_2,y_2)#, then #[Slope](http://socratic.org/algebra/graphs-of-linear-equations-and-functions/slope) = (y_2-y_1)/(x_2-x_1)#
    Here, the coordinates are # (8,5)# and #(-4,7)#

#Slope = (7-5)/(-4-8)=2/-12=-1/6#

The slope of the line passing through points # (8,5)# and #(-4,7)# is #color(green)(-1/6#

  • The graph of the line will look like this:

graph{y=(-x/6)+(38/6) [-16.01, 16.02, -8, 8.03]}