Question

How do you find the equation of the tangent line of the function `(3x-4)/(x-2)^2` through the point (2,0)?

Answer 1

When `x=2` then the function is undefined, as the denominator `(x-2)^2` becomes zero.

So the tangent line will be the asymptote at `x=2` and that is your answer.
graph{(3x-4)/(x-2)^2 [-32, 32.93, -5.37, 27.12]}