Question

How do you solve for z in `a = x+y+z/3`?

Answer 1

The answer is `z=3(a-x-y)`.

Beginning Equation:

`a=x+y+z/3`

First multiply both sides of the equation by 3.

`3a=3x+3y+z`

Subract 3x and 3y from both sides.

`3a-3x-3y=z`

Factor out the 3.

`3(a-x-y)=z`