How do you multiply #(30a^2)/(18b)*(6b)/(5a)#?

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Answer 1 · 2015-04-09T16:37:53

The answer is #2a#.

Multiply both numerators and both denominators, then simplify.

#(30a^2)/(18b)*(6b)/(5a)# =

#(180a^2b)/(90ab)# =

Reduce #180/90# to #2# =

#(2a^2b)/(ab)# =

Reduce #a^2/a# to #a#.

#(2ab)/(b)# =

Cancel the b in the numerator and denominator.

#(2acancel(b))/(cancel(b))# =

#2a#