How do you differentiate y = cos sec^2(x)? Calculus Differentiating Trigonometric Functions Derivatives of y=sec(x), y=cot(x), y= csc(x) 1 Answer Anees Apr 13, 2015 (dy)/(dx)=-2sec^2xtanx(sinsec^2(x)) y=(cossec^2(x)) Differentiating both side with respect to 'x' (dy)/(dx)=d/(dx)(cossec^2(x)) (dy)/(dx)=-sinsec^2(x)d/(dx)(sec^2(x)) (dy)/(dx)=-sinsec^2(x)(2secx)(d/(dx)(secx)) (dy)/(dx)=-sinsec^2(x)(2secx)(secxtanx) (dy)/(dx)=-sinsec^2(x)(2sec^2xtanx) (dy)/(dx)=-2sec^2xtanx(sinsec^2(x)) Answer link Related questions What is Derivatives of y=sec(x) ? What is the Derivative of y=sec(x^2)? What is the Derivative of y=x sec(kx)? What is the Derivative of y=sec ^ 2(x)? What is the derivative of y=4 sec ^2(x)? What is the derivative of y=ln(sec(x)+tan(x))? What is the derivative of y=sec^2(x)? What is the derivative of y=sec^2(x) + tan^2(x)? What is the derivative of y=sec^3(x)? What is the derivative of y=sec(x) tan(x)? See all questions in Derivatives of y=sec(x), y=cot(x), y= csc(x) Impact of this question 3340 views around the world You can reuse this answer Creative Commons License