How do you find integral of #((secxtanx)/(secx-1))dx#?
2 Answers
We know that :
So, we have :
Let's
So
Factorize
With decomposition in simple elements, we have :
So :
We have :
We get :
Another way of doing this is to consider that
That is, the derivative of
This is the same as letting
We then have,