How do you multiply #6a ^ -4 (a ^ 5 + 3x ^2 )#?

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Answer 1 · 2015-04-14T05:27:48

The Distributive Property of Multiplication tells us that
#color(blue)(a*(b+c) = a*b + a*c#

#6a ^ -4 (a ^ 5 + 3x ^2 )#

# = (6a ^ -4 *a ^ 5) + (6a ^ -4)(3x ^2 )#

# = {6*(a ^ -4 *a ^ 5) } + {(6*3)(a ^ -4)(x ^2 )}#

#color(blue)(a^m * a^n = a ^(m+n)#

# = {6*a ^ (-4 + 5) } + {18(a ^ -4)(x ^2 )}#

# = 6*a + {18(a ^ -4)(x ^2 )}#

#color(green)( = 6*a + 18(x ^2 / a^4)#