How do you know why Rolle's Theorem does not apply to #f(x)= x^(2/3)# on the interval [-1,1]?

1 Answer
Apr 18, 2015

#f(x)= x^(2/3)# on the interval [-1,1]

H1
Is the function continuous on the closed interval?

Yes, power functions are continuous on their domains.

H2
Is the function differentiable on the open interval?

No.

#f'(x) = 2/(3 root(3) x)# does not exist at #x = 0#. The function is not differentiable on any interval that includes #0#

(By the way, H3 #f(-1)=f(1)# is true for this function.)

Also by the way: This function does not satisfy the conclusion of Rolle's Theorem on any interval, because there is no solution to:

#f'(x) = 2/(3 root(3) x) = 0#