How do you integrate #2xsin(x)dx#? Calculus Techniques of Integration Integration by Parts 1 Answer GiĆ³ Apr 22, 2015 I would use integration by Parts: #int2xsin(x)dx=2[-xcos(x)+int1*cos(x)dx]=-2xcos(x)+2sin(x) +c# Answer link Related questions How do I find the integral #int(x*ln(x))dx# ? How do I find the integral #int(cos(x)/e^x)dx# ? How do I find the integral #int(x*cos(5x))dx# ? How do I find the integral #int(x*e^-x)dx# ? How do I find the integral #int(x^2*sin(pix))dx# ? How do I find the integral #intln(2x+1)dx# ? How do I find the integral #intsin^-1(x)dx# ? How do I find the integral #intarctan(4x)dx# ? How do I find the integral #intx^5*ln(x)dx# ? How do I find the integral #intx*2^xdx# ? See all questions in Integration by Parts Impact of this question 20430 views around the world You can reuse this answer Creative Commons License