How do you differentiate #d/dx 5^2x^2#?

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Answer 1 · 2015-04-25T20:43:00

In genera; an expression of the form #ax^b# can be differentiated (with respect to #x#) as #(b*a)x^(b-1)#

#(d 5^2x^2)/(dx) = (2*5^2)x = 50x#
or to phrase it another way the derivative of #5^2x^2 " is " 50x#
and that is (probably?) what you want...

...if you really wanted the derivative of #(d 5^2x^2)/(dx)#
then you are asking for the second derivative:
#(d (d 5^2x^2)/(dx))/(dx) = 50#

Answer 2 · 2015-04-27T18:38:07

50x

#color(green)(Solution)#

#d/dx5^2x^2#

Bring the constant #color(blue)(5^2)# outside the #d/dx#

So,

#=5^2d/dxx^2#

#=25(2x)#

#=50x#