How do I find the antiderivative for #(1/sqrt(x) + 2/x^3) dx#?

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Answer 1 · 2015-04-27T21:51:10

You can write it as:
#int1/sqrt(x)dx+int2/x^3dx=#
#=intx^(-1/2)dx+2intx^-3dx=#
and integrate them remembering that:
#intx^ndx=x^(n+1)/(n+1)+c#