Question

Question #ae278

Answer 1

`Eff = W/Q_(hot)`
where `Q_(hot)` is the heat absorbed from hot reservoir and,
W = 1250 J (Work done by heat engine)

therefore, `Q_(hot) = 1250/0.24 = 5208.33` J (Answer A)

Now, `W = Q_(hot) - Q_(cold)`
where `Q_(cold)` is the heat transferred to cold reservoir.

Implies,
`Q_(cold) = Q_(hot) - W = 5208.33 - 1250 = 3958.33` J (Answer B)