How do you factor #x^3 + 3x^2 - 4x - 12#?

1 Answer
Gió
Apr 28, 2015

Collect #x# between the first and third term and #3# between the second and fourth.
After this collect the bracket and you'll get your two factors.

If you have difficulties have a look at the solution below.
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Solution:
#x(x^2-4)+3(x^2-4)=#
#(x^2-4)(x+3)#

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