How do you factor by grouping $3x^3+2x^2+3x+2$ ?

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Answer 1 · 2015-04-30T08:43:10

we are given, 3 $x^3$ $+$ 2 $x^2$ $+$ 3 $x$ $+$ 2

on rearrangement:

$=$ 3 $x^3$ $+$ 3 $x$ $+$ 2 $x^2$ $+$ 2

The first two terms have 3 $x$ in common and the last two terms have 2 in common:

taking out the common terms:
$=$ 3 $x$ ( $x^2$ + 1) $+$ 2 ( $x^2$ $+$ 1)

making groups of two:
$=$ (3 $x$ $+$ 2) ( $x^2$ $+$ 1 )

How do you factor by grouping 3x^3+2x^2+3x+23x^3+2x^2+3x+2?