How do you factor by grouping $2x^3 - x^2 - 6x + 3$ ?

Question

2280 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-30T08:58:37

we are given, 2 $x^3$ $-$ $x^2$ $-$ 6 $x$ $+$ 3

The first two terms have $x^2$ in common and the last two terms have 3 in common:

taking out the common terms:

$=$ $x^2$ (2 $x$ $-$ 1) $+$ 3 ( $-$ 2 $x$ $+$ 1)

$=$ $x^2$ (2 $x$ $-$ 1) $-$ 3 (2 $x$ $-$ 1)

making groups of two,

$=$ ( $x^2$ $-$ 3) (2 $x$ $-$ 1)

How do you factor by grouping 2x^3 - x^2 - 6x + 32x^3 - x^2 - 6x + 3?