How do you write #y=x^2-4x+2# into vertex form?

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Answer 1 · 2015-04-30T12:40:53

The vertex form of a quadratic function is given by
#y = a(x - h)^2 + k#, where #(h, k)# is the vertex of the parabola.

We can use the process of Completing the Square to get this into the Vertex Form.

#y=x^2-4x+2#

#-> y - 2 = x^2 - 4x# (Transposed 2 to the Left Hand Side)

Now we ADD #4# from each side to complete the square

#-> y - 2 + 4 = x^2 - 4x + 2^2#

#-> y + 2 = (x-2)^2 #

#-> color(green)( y =1* (x-2)^2 - 2# is the Vertex Form

The vertex of the Parabola is# {2 , -2}#