How do you solve #(3x − 2)/(4) > 4#?

Question

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Answer 1 · 2015-04-30T17:05:53

#x>6#

Solution

#(3x-2)/4>4#

Multiplying both sides by '4'

#4.(3x-2)/4>4.4#

#cancel4.(3x-2)/cancel4>16#

#3x-2>16#

Adding '2' on both sides

#3x-2+2>16+2#

#3x-cancel2+cancel2>18#

#3x>18#

Dividing both sides by '3'

#(3x)/3>18/3#

#(cancel3x)/cancel3>6#

#x>6#