What is the value of #x# if #sqrt(5x+1) = x+1#?

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Answer 1 · 2015-04-30T19:56:43

#x in {0,3}#

#sqrt(5x+1) = x+1#

#5x+1 = (x+1)^2#

#5x+1 = x^2+2x+1#

#x^2-3x = 0#

#x(x-3) = 0#

Either #x=0# or #(x-3)= 0#

The solutions are
#x=0# and #x=3#