Question

Question #bbfd1

Answer 1

2480.6 kJ required.

For:

`CH_(4(g))+2O_(2(g))rarrCO_(2(g))+2H_2O_((l))`

`DeltaH_(comb)=-882.0"kJ"`

So for the reverse reaction:

`CO_(2(g))+2H_2O_((l))rarrCH_(4(g))+2O_(2(g))`

`DeltaH=+882.0"kJ"`

`[M_r]CH_4=16.0`

So `16.0"g"` requires `882.0"kJ"`

So `1"g"rarr882.0/16.0"kJ"`

So `45"g"rarr(882.0)/(16.0)xx45=2480.0"kJ"`