Question #bbfd1

1 Answer
Michael · Media Owl
Apr 30, 2015

2480.6 kJ required.

For:

#CH_(4(g))+2O_(2(g))rarrCO_(2(g))+2H_2O_((l))#

#DeltaH_(comb)=-882.0"kJ"#

So for the reverse reaction:

#CO_(2(g))+2H_2O_((l))rarrCH_(4(g))+2O_(2(g))#

#DeltaH=+882.0"kJ"#

#[M_r]CH_4=16.0#

So #16.0"g"# requires #882.0"kJ"#

So #1"g"rarr882.0/16.0"kJ"#

So #45"g"rarr(882.0)/(16.0)xx45=2480.0"kJ"#

Related questions
See all questions in Enthalpy
Impact of this question
1913 views around the world
You can reuse this answer
Creative Commons License