How do you use the difference of two squares formula to factor #3(b+5)² - 48#?

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Answer 1 · 2015-05-03T17:20:16

In this way:

#3(b+5)^2-48=3[(b+5)^2-16]=#

#=3(b+5-4)(b+5+4)=3(b+1)(b+9)#.

Answer 2 · 2015-05-03T17:22:49

Difference of squares equation:
#(a^2-b^2) =(a+b)(a-b)#

#3(b+5)^-48#

#=3( (b+5)^2 -4^2)#

#=3( (b+5)+4)((b+5)-4)#

#=3(b+9)(b+1)#