How do you factor #-8w+49w^2+14w^3-28#?

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Answer 1 · 2015-05-04T18:24:23

Collect #2w# between the first and third term and #7# between the second and rourth:
#2w(-4+7w^2)+7(7w^2-4)=# collect #(7w^2-4)#
#=(7w^2-4)(2w+7)#