Question

How do you factor `x^3 + (2)x^2 + (4)x + 8`?

Answer 1

`x^3+2x^2+4x+8=(x+2)(x^2+4)=(x+2)(x+2i)(x-2i)`

The solution to a cubic is not simple. This one has an 'obvious' factor.Rewrite the equation `x^3+4x +2x^2+8=x(x^2+4)+2(x^2+4)=(x+2)(x^2+4)`