Question

How do you use the law of sines to solve the triangle given A = 14.9°, B = 98.1°, b = 21.5?

Answer 1

The Law of sines is `SinA/a=SinB/b`

`A=14.9°` `B=98.1°` `b=21.5`

So where looking for `a`

`=> a=(bsinA)/sinB=(21.5xxsin14.9°)/(sin98.1°)=5.58`