How do you write Equation of a line that goes through (8,5) and is perpendicular to 2x-y=7 in slope intercept form and standard form?

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Answer 1 · 2015-05-05T20:23:04

Converting #2x-y=7# into a slope-intercept form:
#y = 2x+7#

The slope of #2x-y=7# is #2#

So the slope of the required line is #-1/2#
(the slopes of perpendicular lines are the negative inverse of each other)

We are looking for a line with slope #m=-1/2# which passes through
#(x_1,y_1)=(8,5)#

In slope-point form this is
#(y-5)=(-1/2)(x-8)#

Converting to slope intercept form:
#y =-1/2x+9#

and in standard form
#x+2y = 18#