Question #15e3f

1 Answer
bp
May 8, 2015

x=4, #(7-sqrt129)/2#

First solve 24+2-#x^2#= 5x-4,that is #x^2# +3x-28=0 , or(x+7)(x-4)=0, giving x= -7, 4.

Next solve #24+2x-x^2#= -5x+4, that is #x^2 -7x-20=0#, giving x=#(7+sqrt129)/2#, #(7-sqrt129)/2#.

Out of these four values, it can be verified that only x=4, #(7-sqrt129)/2# satisfy the given equation.

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