How to find the x and y-intercept given #y= 4x-2#?

1 Answer
May 9, 2015

#I_x ={x#-intercept#}={(1/2,0)}#
#I_y ={y#-intercept#}={(0,-2)}#

The intercepts are made combining the equation of the two functions together

So, you know the equation of the #x# axis is #y=0#, and the equation of the #y# axis is #x=0#)
#I_x={y=4x-2# #&# #y=0},I_y={y=4x-2# #&# #x=0}#
so

#I_x={(x,0) : 4x-2=0}={(1/2,0)}#
#I_y={(0,y):y=4*0-2}={(0,-2)}#

graph{4x-2 [-10, 10, -5, 5]}