How do you simplify #(9sqrt5)/sqrt3#?

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Answer 1 · 2015-05-09T22:23:55

Simplify #(9sqrt5)/sqrt3# .

Rationalize the denominator by multiplying the numerator and denominator times #sqrt3#.

#(9sqrt5)/sqrt3xxsqrt3/sqrt3# =

#(9sqrt5xxsqrt3)/3#=

Simplify.

#(9sqrt5sqrt3)/3#=

#(9sqrt15)/3# =

Simplify.

#(9/3)sqrt15# =

#3sqrt15#