How do you find the equation for a parabola with an axis of symmetry of x=3 and points (1,0) and (-4,3)?
1 Answer
May 10, 2015
Equation
axis of symmetry:
y passes at point (1, 0) and point (-4, 3)
0 = a + b + c (2) -> c = - a - b = - a + 6a = 5a
3 = 16a - 4b + c (3) -> 3 = 16a + 4(6a) + 5a = 16a + 24a + 5a = 45a
45a = 3 --> a = 3/45 = 1/15
b = -6/15
c = 5/15
Equation
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