Question

How do you solve `3(abs(x-1)+2)=30`?

Answer 1

The solutions are `x = -7` and `x = 9`.

Starting with `3(|x-1|+2)=30`, first divide both sides by 3 to give:
`|x-1|+2=10`.

Subtract 2 from both sides to give:
`|x-1|=8`

Hence
`x-1=+-8`

Add 1 to both sides to get:
`x = +-8 + 1`

So `x=-8+1=-7` or `x=8+1=9`.