What is the solution set of #4[9^(x-1)] = 108#?

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Answer 1 · 2015-05-10T21:32:18

Take 4 to the right:
#9^(x-1)=108/4=27#
#9^(x-1)=3^3#
But #9=3^2# so:
#3^(2(x-1))=3^3#
And:
#2(x-1)=3#
#2x-2=3#
#x=5/2#