How do you factor #6z^2+12z-az-2a#?

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Answer 1 · 2015-05-11T11:31:56

We can factor the expression by making groups of 2 terms:

#(6z^2+12z)-(az+2a)#

#6z# is a factor common to both the terms in the first group and
#a# is a factor common to both the terms in the second group

We can write it as

#= 6z(z+2) - a(z+2)#

#z+2# is common to both the terms in the expression

#= color(green)((z+2)(6z-a)#