What is the average rate of change of the function #y = x^2+1# over the interval #[5, 5+a]# ?

1 Answer
May 12, 2015

The average rate of change will be the total change in #y# divided by the total change in #x#, so we just have to look at the values at each end of the given interval:

When #x = 5#

#y = 5^2+1 = 26#.

When #x = 5 + a#:

#y = (5+a)^2 + 1 = 25+10a+a^2+1#

#= 26+10a+a^2#

#Delta y = (26+10a+a^2)-26 = 10a+a^2#

#Delta x = (5+a)-5 = a#

So #(Delta y)/(Delta x) = (10a + a^2)/a = 10+a#