What is the factors for #14x^2 y+ 4xy^2 +2xy#?

1 Answer

You must check what elements you have in common for all these three factors. Let's just expand them a little:

#7*color(green)(2)*color(blue)(x)*x*color(red)(y) + color(green)(2)*2*color(blue)(x)*color(red)(y)*y + color(green)(2)*color(blue)(x)*color(red)(y)#

Now, we can see that these elements (#2xy#) are multiplying all the three factors, as follows:

#color(green)(2)color(blue)(x)color(red)(y)(7x + 2y + 1)#