Why does B(CH3)3 violate the octet rule?

1 Answer
May 14, 2015

#"B(CH"_3)_3# violates the octet rule because the #"B"# atom has only six valence electrons in its valence shell.

The octet rule is a chemical rule of thumb that states that atoms of main-group elements combine in such a way that each atom will have eight electrons in its valence shell.

The Lewis structure of #"B(CH"_3")"_3# is

upload.wikimedia.org

We see that the molecule has only six valence electrons around the #"B"# atom.

This is a violation of the octet rule.