Question

How do you simplify `sqrt2/sqrt10`?

Answer 1

`sqrt 2 / sqrt 10 = sqrt 2 / (sqrt 2 xx sqrt 5)`

`sqrt 2 / sqrt 10 = cancelsqrt 2 / (cancelsqrt 2 xx sqrt 5)`
`= 1 / sqrt5`

rationalizing the denominator
multiplying the numerator and denominator by `sqrt5`
`1/(sqrt5) = (1 xx sqrt5) / (sqrt5 xx sqrt5)`
`= sqrt5/5`