How to find the y-intercept given #x^2+14+1#?

2 Answers
Nghi N.
May 15, 2015

Please check your question. y = x^2 + 14x + 1 ?

Alan P.
May 15, 2015

Possibility 1
Assuming your equation is
#y = x^2 + 14 +1#
then
#y = x^2+15#

The y-intercept is the value of #y# when #x=0#
So the y-intercept in this case would be #15#

Possibility 2 (you meant #14x#)
#y=x^2+14x+1#

Again, the y-intercept is the value of #y# when #x=0#
So, in this case, the y-intercept is #1#

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